A charged particle is placed in an external magnetic field and it is moving in a circular path of radius 26m.The magnetic force acting on th

Question

A charged particle is placed in an external magnetic field and it is moving in a circular path of radius 26m.The magnetic force acting on the particle is 16N.What is the kinetic energy of the particle

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Acacia 4 years 2021-08-11T18:55:16+00:00 1 Answers 22 views 0

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  1. thienan
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    2021-08-11T18:57:07+00:00
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    Answer:

    208 Joules

    Explanation:

    The radius of the circular path the charge moves, r = 26 m

    The magnetic force acting on the charge particle, F = 16 N

    Centripetal force, F_c = m·v²/r

    Kinetic energy, K.E. = (1/2)·m·v²

    Where;

    m = The mass of the charged particle

    v = The velocity of the charged particle

    r = The radius of the path of the charged particle

    Whereby the magnetic force acting on the charge particle = The centripetal force, we have;

    F = F_c = m·v²/r = 16 N

    (1/2) × r × F_c = (1/2) × r × m·v²/r = (1/2)·m·v² = K.E.

    ∴ (1/2) × r × F_c = (1/2) × 26 m × 16 N =  = (1/2)·m·v² = K.E.

    ∴ 208 Joules = K.E.

    The kinetic energy of an particle moving in the circular path, K.E. = 208 Joules.

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