A charge q1 of −6.00 × 10−9 C and a charge q2 of − 3.00 × 10−9 C are separated by a distance of 60.0 cm. Where could a third charge be place

Question

A charge q1 of −6.00 × 10−9 C and a charge q2 of − 3.00 × 10−9 C are separated by a distance of 60.0 cm. Where could a third charge be placed so that the net electric force on it is zero?

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Latifah 3 years 2021-08-06T17:03:12+00:00 2 Answers 161 views 0

Answers ( )

  1. taiduc
    0
    2021-08-06T17:04:35+00:00
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    Answer: 35.2 cm from q1 and 24.8 cm from q2.

  2. thachthao
    0
    2021-08-06T17:04:45+00:00
    Reply

    Answer:

    The third charge be placed at a distance of 30 cm from first charge such that the net electric force on it is zero.

    Explanation:

    Given that,

    Charge 1, q_1=-6\times 10^{-9}\ C

    Charge 2, q_2=-3\times 10^{-9}\ C

    The distance between charges, d = 60 cm

    Let the third charge is placed at a distance of x from first charge. So, it will be at a distance of (0.6-x) from charge 2. So,

    k\dfrac{q_1q_2}{x^2}=k\dfrac{q_1q_2}{(60-x)^2}\\\\\dfrac{1}{x^2}=\dfrac{1}{(60-x)^2}\\\\\dfrac{1}{x^2}=\dfrac{1}{3600+x^2-120x}\\\\x=30\ cm

    So, the third charge be placed at a distance of 30 cm from first charge such that the net electric force on it is zero.

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