A buffer solution contains 0.368 M hydrocyanic acid and 0.360 M potassium cyanide . If 0.0513 moles of sodium hydroxide are added to 225 mL

Question

A buffer solution contains 0.368 M hydrocyanic acid and 0.360 M potassium cyanide . If 0.0513 moles of sodium hydroxide are added to 225 mL of this buffer, what is the pH of the resulting solution

in progress 0
Neala 3 years 2021-07-21T22:06:44+00:00 1 Answers 5 views 0

Answers ( )

  1. Eirian
    0
    2021-07-21T22:08:01+00:00
    Reply

    Solution :

    Millimoles of hydrocyanic acid = 225 x 0.368

                                                       = 82.8

    Millimoles of potassium cyanide = 225 x 0.360

                                                       = 81

    Millimoles of sodium hydroxide = 51.3

    Therefore,

    pOH = pKb + log [salt – C / bas + C]

            = 4.74 + log[82.8 – 51.3 / 81 + 51.3]

             = 4.102

    Therefore, pH = 9.05

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )