A body is thrown vertically upward with velocity 20m/s .How long time it remains in air? (g=10m/s2) ​

Question

A body is thrown vertically upward with velocity 20m/s .How long time it remains in air? (g=10m/s2)

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Thu Thảo 4 years 2021-08-03T20:45:17+00:00 2 Answers 53 views 0

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    0
    2021-08-03T20:46:56+00:00

    Answer:

    \boxed{\sf Time \ being \ in \ which \ body \ remains \ in \ air = 4 \ s}

    Given:

    Velocity (u) = 20 m/s

    Acceleration due to gravity (g) = 10 \sf m/s^2

    To Find:

    Time (t) being in which body remains in air.

    Explanation:

    Formula:

    \boxed{\bold{\sf t=\frac{2u}{g}}}

    Substituting values of u & g in the equation:

    \sf \implies t = \frac{2 \times 20}{10}

    \sf \implies t =\frac{40}{10}

    \sf \implies t =\frac{4 \times \cancel{10}}{ \cancel{10}}

    \sf \implies t = 4 \ s

    \therefore

    Time (t) being in which body remains in air = 4 seconds

    0
    2021-08-03T20:47:08+00:00

    I don’t know, it depends if they have a parachute and can deploy it quickly enough. If they do, the drag and air resistance would gently bring them down at a much slower pace than freefalling. Not enough information to solve this.

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