A block with mass m = 4.5 kg is attached to two springs with spring constants kleft = 36 N/m and kright = 50 N/m. The block is pulled a dist

Question

A block with mass m = 4.5 kg is attached to two springs with spring constants kleft = 36 N/m and kright = 50 N/m. The block is pulled a distance x = 0.25 m to the left of its equilibrium position and released from rest. 1)What is the magnitude of the net force on the block (the moment it is released)?

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Tài Đức 4 years 2021-08-05T20:43:34+00:00 1 Answers 13 views 0

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  1. giabao
    0
    2021-08-05T20:45:20+00:00
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    Answer:

    21.5 N

    Explanation:

    As the block is pulled to a distance of 0.25 m to the left of its equilibrium position, the left spring is compressed by x = 0.25 m and exerting an elastic force to the right, the right spring is stretched by x =0.25 m and also exerting an elastic force to the right. Knowing their spring constant, we can calculate the total net force at that instant

    F = F_{left} + F_{right}

    F = k_{left}x + k_{right}x

    F = x(k_{left} + k_{right}) = 0.25(36 + 50) = 0.25*86 = 21.5 N

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