A 50kg crate is being push on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floo

Question

A 50kg crate is being push on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floor is hk=0.1 . What is the push force?​

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Mít Mít 3 years 2021-09-05T13:19:17+00:00 1 Answers 94 views 0

Answers ( )

  1. quangkhai
    0
    2021-09-05T13:20:50+00:00
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    Answer:

      F = 49 N

    Explanation:

    For this exercise we must use Newton’s second law. Let’s set a reference frame with the x axis parallel to the floor.

    As they indicate that the box is going at constant speed, its acceleration is zero

    Y axis y

           N-W = 0

           N = mg

    X axis

            F-fr = 0

            F = fr

    the friction force has the formula

          fr = μ N

          fr = μ mg

    we substitute

                F = μ m g

    let’s calculate

                F = 0.1 50 9.8

                F = 49 N

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