A 500-N box is pushed across a horizontal floor with a force of 250 N. The coefficient of kinetic friction is 0.4 Find the work done in push

Question

A 500-N box is pushed across a horizontal floor with a force of 250 N. The coefficient of kinetic friction is 0.4 Find the work done in pushing the box 20 m. How much work went into overcoming friction and how much into accelerating the box?

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Vân Khánh 4 years 2021-08-28T06:23:43+00:00 1 Answers 68 views 0

Answers ( )

  1. ngochoa
    0
    2021-08-28T06:25:20+00:00
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    Answer:

    Explanation:

    W = Fd

    work input to the box

    W = 250(20) = 5000 J

    work of friction

    Wf = μ(mg)d = 0.4(500)(-20) = -4000 J

    Kinetic energy change (accelerating the box)

    5000 – 4000 = 1000 J

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