a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceler

Question

a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J​

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Nick 4 years 2021-08-05T09:33:16+00:00 1 Answers 47 views 0

Answers ( )

  1. Calantha
    0
    2021-08-05T09:34:29+00:00
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    Answer:

    c. -288 J

    Explanation:

    Given;

    mass of the block, m = 4 kg

    velocity of the block, v = 12 m/s

    deceleration of the block, a = 3 m/s²

    Apply work-energy theorem;

    work done in stopping the block = kinetic energy of the block

    W = ¹/₂mv²

    where;

    W is the magnitude of the work done by the force

    W = ¹/₂ x 4 x 12²

    W = 288 J

    Since the work done by the force is in opposite direction, then the value of the work done by the force is –288 J

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