A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full power and good

Question

A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full power and good tires on good pavement, the maximum forward force on the truck is 18,000 N.

Part A

What is the maximum possible acceleration the truck can give the SUV?

Express your answer to two significant figures and include the appropriate units.

a =

Part B

At this acceleration, what is the force of the SUV’s bumper on the truck’s bumper?

Express your answer to two significant figures and include the appropriate units.

Fsuv on truck =

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RobertKer 4 years 2021-07-24T02:05:45+00:00 2 Answers 81 views 0

Answers ( )

  1. phucdien
    0
    2021-07-24T02:06:45+00:00
    Reply

    Answer:

    a) a_{max} = 3.8\,\frac{m}{s^{2}}, b) F = 9260\,N

    Explanation:

    a) The maximum possible acceleration that the truck can give to the SUV is:

    a_{max} = \frac{18,000\,N}{2,400\,kg+2300\,kg}

    a_{max} = 3.8\,\frac{m}{s^{2}}

    b) The equation of equilibrium for the truck is:

    18,000\,N - F = (2,300\,kg)\cdot (3.8\,\frac{m}{s^{2}})

    The force of the SUV’s bumper on the truck’s bumper is:

    F = 9260\,N

  2. Philomena
    0
    2021-07-24T02:07:03+00:00
    Reply

    Answer:

    A) the maximum possible acceleration = 3.83 m/s²

    B) F(SUV bumper) = 2400  kg *3.83 m/s² = 9192 N = 92 * 10² N

    Explanation:

    Step 1: Data given

    Mass of the truck = 2300 kg

    Mass of the SUV = 2400 kg

    The maximum forward force on the truck is 18000 N

    Step 2: What is the maximum possible acceleration the truck can give the SUV?

    Total mass = MAss truck + mass SUV

    Total mass = 2300 kg + 2400 kg

    Total mass = 4700 kg

    Acceleration = Force / mass

    The maximum possible acceleration = 18000 N / 4700 kg

    the maximum possible acceleration = 3.83 m/s²

    Step 3: At this acceleration, what is the force of the SUV’s bumper on the truck’s bumper?

    F = m * a

    F(trucks bumper) = 2300 kg *3.83 m/s² = 8809 N

    F(SUV bumper) = 2400  kg *3.83 m/s² = 9192 N = 92 * 10² N

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