A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ball is also t

Question

A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ball is also thrown at the same speed horizontally at the wall, but sticks to it upon hitting. [THE CLAY BALL / THE RUBBER BALL /NEITHER] (circle one) exerts a greater magnitude of impulse on the wall. Briefly explain (either in words or calculations)

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Thu Thủy 4 years 2021-08-22T04:04:46+00:00 1 Answers 14 views 0

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  1. Doris
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    2021-08-22T04:06:13+00:00
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    Answer:

    THE RUBBER BALL

    Explanation:

    From the question we are told that

          The mass of the rubber ball is m_r = 2 \ kg

          The  initial  speed of the rubber ball is  u = 3 \ m/s

          The final speed at which it bounces bank v - 3 \ m/s

          The mass of the clay ball  is  m_c = 2 \ kg

           The  initial  speed of the clay  ball is u = 3 \ m/s

           The final speed of the clay ball is  v = 0 \ m/s

    Generally Impulse is mathematically represented as

           I = \Delta p

    where \Delta p is the change in the linear momentum so  

           I = m(v-u)

    For the rubber  is  

            I_r = 2(-3 -3)

           I_r = -12\ kg \cdot m/s

    =>     |I_r| = 12\ kg \cdot m/s

    For the clay ball

           I_c = 2(0-3)

            I_c = -6 \ kg\cdot \ m/s

    =>    | I_c| = 6 \ kg\cdot \ m/s

    So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

           

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )