A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.9-T magnetic field. The loop is rotated so that its plane is para

Question

A 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.9-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.15 s.What is the average induced emf in the loop?

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Thái Dương 5 years 2021-08-29T22:36:14+00:00 1 Answers 17 views 0

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  1. Vodka
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    2021-08-29T22:37:26+00:00
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    Answer:

    0.3405V

    Explanation:

    #Given a magnetic field of 1.9T, diameter= 18.5cm(r=9.25cm or 0.0925m), we find the magnetic flux of the loop as:

    \phi=B.(\pi r^2)cos 0\textdegree\\=1.9\pi\times 0.0925^2 \times cos 0\textdegree\\=5.107\times10^-^2 \ Tm^2

    we can now calculate the induced emf, \frac{\phi}{\bigtriangleup t}:

    \frac{\phi}{\bigtriangleup t}=\frac{5.107\times 10^-^2}{0.15}\\=3.405\times 10^-^1V

    Hence, the induced emf of the loop is 0.3405V

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