A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes and the car

Question

A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes and the car comes to a rest uniformly in a distance of 240 m. What are the magnitude and direction of the net force applied to the car to bring it to rest?

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Calantha 4 years 2021-08-31T13:03:54+00:00 1 Answers 37 views 0

Answers ( )

  1. Bo
    0
    2021-08-31T13:05:22+00:00
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    Answer:

    The value of F= – 830 N

    Since the force is negative, it implies direction of the force applied was due south.

    Explanation:

    Given data:

    Mass = 1000-kg

    Distance, d = 240 m

    Initial velocity, v1 = 20.0 m/s

    Final velocity, v2 = 0 (since the car came to rest after brake was applied)

    v2²= v1² + 2ad (using one of the equation of motion)

    0=  20² + (2 x a x  240)

    0= 400 + 480 a

    a = – 400/480

    a = – 0.83 m/s²

    Then, imputing the value of a into

    F = ma

    F = 1000 kg x ( – 0.83 m/s²)

    F= – 830 N

    The car was driving toward the north, and since the force is negative, it implies direction of the force applied was due south.

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