(x+5)^3-3=-67 11-(2x-3)^2=2

Question

(x+5)^3-3=-67
11-(2x-3)^2=2

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Khang Minh 4 years 2020-11-27T02:11:25+00:00 2 Answers 64 views 0

Answers ( )

  1. Eirian
    0
    2020-11-27T02:12:46+00:00
    Reply

    Đáp án:

     

    Giải thích các bước giải:

    $a) (x+5)^3-3=-67$

    $→(x+5)^3=-67+3$

    $→(x+5)^3=-64$

    $→(x+5)^3=(-4)^3$

    $⇔x+5=-4$

    $→x=-4-5$

    $→x=-9$

    $b) 11-(2x-3)^2=2$

    $→(2x-2)^2=11-2$

    $→(2x-2)^2=9$

    $→(2x-2)^2=3^2$

    $→2x-2=±3$

    $⇒$\(\left[ \begin{array}{l}(+)2x-2=3\\⇒2(x-1)=3\\⇒x-1=\dfrac{3}{2}\\⇒x=\dfrac{3}{2}+1\\⇒x=\dfrac{5}{2}\\(+)2x-2=-3\\⇒2(x-1)=-3\\⇒x-1=\dfrac{-3}{2}\\⇒x=\dfrac{-3}{2}+1\\⇒x=\dfrac{-1}{2}\end{array} \right.\) 

    Vậy $x=\dfrac{5}{2}$ hoặc $x=\dfrac{-1}{2}$

    Xin hay nhất

  2. sori
    0
    2020-11-27T02:13:16+00:00
    Reply

    a, `(x+5)^3-3=-67`

    `=> (x+5)^3=-64`

    `=> x + 5= -4`

    `=> x = -9`

    b, `11-(2x-3)^2=2`

    `=> (2x-3)^2=9`

    `=>` 2x – 3 = 3 hoặc 2x – 3 = – 3

    `=>` 2x = 6 hoặc 2x = 0

    `=>` x = 3 hoặc x = 0

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )