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x3y3−5x3y5+9y2−8 find coeifecient
Question
x3y3−5x3y5+9y2−8
find coeifecient
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Mathematics
4 years
2021-08-27T05:45:35+00:00
2021-08-27T05:45:35+00:00 1 Answers
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Answer:
The coefficient is 90.
Step-by-step explanation:
Expansion of (a+b)n gives us (n+1) terms which are given by
binomial expansion xnCra(n−r)br, where r ranges from n to 0.
Note that powers of a and b add up to n and in the given problem this n=5.
In (x−3y)5, we need coefficient of x3y2, we have 3rd power of x and as such r=5−3=2
and as such the desired coefficient of x3y2 is given by
x5C2x(5−2)(−3y)2=5×41×2×3(−3y)2
= 10×3×9y2=90x3y2
Hence, the coefficient of x3y2 in (x−3y)5 is