2. Ronu’s present age is “x “years and her sister Shaani’s present age is twice of Ronu’s age. Write following as algebraic expression<

Question

2. Ronu’s present age is “x “years and her sister Shaani’s present age is twice
of Ronu’s age. Write following as algebraic expression
a) Ronu’s present age
b) Ronu’s age after 2 years
c) Shaani’s present age
d) Shaani’s age after 2 years
What hould be added to 100 to get – 132​

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Hồng Cúc 3 years 2021-08-22T16:18:57+00:00 1 Answers 8 views 0

Answers ( )

  1. trucchi
    0
    2021-08-22T16:20:36+00:00
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    Answer:

    x = -232

    Step-by-step explanation:

    Ronu’s present age is “x “years and her sister Shaani’s present age is twice  of Ronu’s age.

    (a) Ronu’s present age = x years

    (b) Ronu’s age after 2 years = (x+2) years

    (c) Shaani’s present age = 2x years

    (d) Shaani’s age after 2 years = (2x+2) years

    Let x should be added to 100 to get -132.

    x+100 = -132

    x = -100-132

    x = -232

    Hence, -232 must be added to 100 to get -132.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )