10. A satellites is in a circular orbit around the earth at a height of 360 km above the earth’s surface. What is its time period? What is i

Question

10. A satellites is in a circular orbit around the earth at a height of 360 km above the earth’s surface. What is its time period? What is its orbital speed?

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Thu Cúc 4 years 2021-09-01T19:21:53+00:00 1 Answers 11 views 0

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  1. thongdat2
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    2021-09-01T19:23:16+00:00
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    Answer:

    Orbital speed=8102.39m/s

    Time period=2935.98seconds

    Explanation:

    For the satellite to be in a stable orbit at a height, h, its centripetal acceleration V2R+h must equal the acceleration due to gravity at that distance from the center of the earth g(R2(R+h)2)

    V2R+h=g(R2(R+h)2)

    V=√g(R2R+h)

    V= sqrt(9.8 × (6371000)^2/(6371000+360000)

    V= sqrt(9.8× (4.059×10^13/6731000)

    V=sqrt(65648789.18)

    V= 8102.39m/s

    Time period ,T= sqrt(4× pi×R^3)/(G× Mcentral)

    T= sqrt(4×3.142×(6.47×10^6)^3/(6.673×10^-11)×(5.98×10^24)

    T=sqrt(3.40×10^21)/ (3.99×10^14)

    T= sqrt(0.862×10^7)

    T= 2935.98seconds

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