1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-34).S)(3.0 x

Question

1. An excited lithium atom emits a red light with wavelength a = 671nm. What is the corresponding photon energy? hc (6.63 x 10-34).S)(3.0 x 108m/s)​

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Xavia 4 years 2021-07-14T05:03:19+00:00 1 Answers 38 views 0

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    2021-07-14T05:04:21+00:00

    Answer:

     E = 2,964 10⁻¹⁹ J

    Explanation:

    The energy of the photons is given by the Planck relation

              E = h f

    the speed of light is related to wavelength and frequency

              c = λ f

    we substitute

              E = h c /λ

    let’s reduce the magnitude to the SI system

              λ = 671 nm = 671 10⁻⁹ m

    let’s calculate

              E = 6.63 10⁻³⁴ 3 10⁸ /671 10⁻⁹

              E = 2,964 10⁻¹⁹ J

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