(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15 help me!!!!! Cần gấp vote 5*

Question

(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15
help me!!!!! Cần gấp vote 5*

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Nick 4 years 2020-12-01T06:15:53+00:00 2 Answers 84 views 0

Answers ( )

  1. giahuy
    0
    2020-12-01T06:17:32+00:00
    Reply

    `(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15`

    `<=>x^3+3x^2+3x+1+3x^2+6x+x^3-x^2+5x^3-5x^2-15=0`

    `<=>(x^3+x^3+5x^3)+(3x^2+3x^2-x^2-5x^2)+(3x+6x)+(1-15)=0`

    `<=>7x^3+9x-14=0`

    `<=>` Nghiệm sấu lắm bạn.

  2. Doris
    0
    2020-12-01T06:17:45+00:00
    Reply

    Giải thích các bước giải:

    `(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15`

    `<=>x^3+3x^2+3x+1+3x^2+6x+x^3-x^2+5x^3-5x^2=15`

    `<=>x^3+3x^2+3x+1+3x^2+6x+x^3-x^2+5x^3-5x^2-15=0`

    `<=>7x^3+9x-14=0`

    `<=>….?`

     

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