Particle A has half the mass and eight times the kinetic energy of particle B. What is the speed ratio vA / vB?

Question

Particle A has half the mass and eight times the kinetic energy of particle B. What is the speed ratio vA / vB?

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RuslanHeatt 4 years 2021-08-27T06:57:12+00:00 1 Answers 299 views 0

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  1. mocmien2
    0
    2021-08-27T06:58:18+00:00
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    Answer:

    Use the equation “KE=½mv²”, and use some algebra. > “Particle A has two times the mass…of particle B” mA = 2mB > “Particle A has…8 situations the kinetic power of particle B” KE_A = 8(KE_B) or: ½(mA)(vA)² = 8(½(mB)(vB)²) the rest is uncomplicated algebra: in basic terms sparkling up the above equation for “vA/vB”. (hint: start up by utilising dividing the two factors by utilising “(mB)(vB)²”. Then make the substitution: mA/mB = 2 (from the 1st eq0.5 ma *  VA^2 = 8 * 0.5 * mb * VB^2

    0.5 * 0.5*mb *  VA^2 = 8 * 0.5 * mb * VB^2

    0.5 * 0.5*  VA^2 = 8 * 0.5 * VB^2

    VA/VB = 4uation))

    Explanation:

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