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P4O10 + 6H20 → 4H3PO4 If 30 g of H2O reacts with 40g of P4O10, what is the limiting reactant? How much H3PO4 can be formed?
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Answers ( )
Answer: is the limiting reagent
66.6 g of will be formed.
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of require 6 moles of
Thus 0.14 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 4 moles of
Thus 0.17 moles of give = of
Mass of
Thus 66.6 g of will be formed.