Need Help ! A 1500 kg car on flat ground is moving 5.25 m/s. Its engine creates a 1250 N forward force as the car moves 42.8

Question

Need Help !
A 1500 kg car on flat ground is
moving 5.25 m/s. Its engine
creates a 1250 N forward force as the car moves 42.8 m. What is its final velocity?​

in progress 0
Ladonna 5 years 2021-08-22T10:56:19+00:00 1 Answers 31 views 0

Answers ( )

  1. thienan
    0
    2021-08-22T10:57:48+00:00
    Reply

    Answer: 5.96m/s

    Explanation:

    Given the following :

    Mass of car (m) = 1500kg

    Velocity (V) = 5.25m/s

    Forward force of engine = 1250N

    Diatance moved = 4.8m

    Final Velocity =?

    Final kinetic energy = Initial kinetic energy + work done by engine

    Initial kinetic energy = 0.5 × mass × velocity^2

    Initial kinetic energy = 0.5 × 1500 × 5.25^2

    Initial kinetic energy = 20671.875 J

    Work done by engine = Force × distance

    Work done by engine = 1250 × 4.8 = 6000J

    Final kinetic energy = (20671.875 + 6000) J

    = 26671.875 J

    From kinetic energy = 0.5mv^2

    26671.875 = 1/2 × 1500 × v^2

    53343.75 = 1500v^2

    v^2 = 35.5625

    v = sqrt(35.5625)

    v = 5.96m/s

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