Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (Note: butterf

Question

Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (Note: butterflies have 6 legs and tarantulas have 8 legs) If T represents the number of tarantulas and B represents the number of butterflies, complete the below system of equations.

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Thái Dương 4 years 2021-07-31T00:25:14+00:00 1 Answers 23 views 0

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  1. Vodka
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    2021-07-31T00:27:07+00:00
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    Answer:

    The solution to this system of equations is:

    • B = 28
    • T = 19

    Step-by-step explanation:

    We are given that Jill has 47 bugs and counts a total 320 legs.

    We can concur that by adding the total number of butterflies and the total number of tarantulas, we will get 47 bugs.

    \text{tarantulas + butterflies} = 47

    We are also told that T is tarantulas and B is butterflies.

    T + B = 47

    Then, we also know that butterflies have 6 legs and tarantulas have 8 legs. So, for every tarantula, we get a multiple of 8 and for butterflies, we get a multiple of 6. This gives us a new equation:

    6B + 8T = 320

    Now, we can set up a system of equation.

    \displaystyle \left \{ {{B + T = 47} \atop {6B + 8T = 320}} \right.

    Using the first equation, we can solve for B.

    \displaystyle B + T = 47\\\\B + T - T = 47 - T\\\\B = 47 - T

    Then, we can substitute this value of B into the second equation and solve for T.

    \displaystyle 6(47-T)+8T=320\\\\282 - 6T + 8T = 320\\\\282 + 2T = 320\\\\2T + 282 = 320\\\\2T + 282 - 282 = 320 -282\\\\2T = 38\\\\\frac{2T}{2}=\frac{38}{2}\\\\T = 19

    Finally, we can substitute this value of T into the first equation to solve for B.

    B + 19 = 47\\\\B + 19 - 19 = 47 - 19\\\\B = 28

    Therefore, the solution to this system of equations is:

    • B = 28
    • T = 19

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