James cut out four parallelograms, the dimensions of which are shown below. Parallelogram 1 length: 12 in. width: 15 in. diagonal: 20 in. Pa

Question

James cut out four parallelograms, the dimensions of which are shown below. Parallelogram 1 length: 12 in. width: 15 in. diagonal: 20 in. Parallelogram 2 length: 16 in. width: 30 in. diagonal: 34 in. Parallelogram 3 length: 20 in. width: 21 in. diagonal: 29 in. Parallelogram 4 length: 18 in. width: 20 in. diagonal: 26 in. James put the parallelograms together so one vertex from each paper exists on a point, as shown in the circle. 4 parallelograms are put together so that one vertex from each paper exists on a point. Which statement explains whether or not the parallelgrams can be put together so each occupies one-quarter of the area of the circle without overlapping any other pieces? Check all that apply.

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Thiên Ân 4 years 2021-07-30T23:59:53+00:00 2 Answers 328 views 0

Answers ( )

  1. Neala
    0
    2021-07-31T00:01:18+00:00
    Reply

    Answer:

    B. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

    E. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

    Step-by-step explanation:

    P1: 12^2+15^2=20^2  144+225=400  369=400

    P2: 16^2+30^2=34^2  256+900=1156  1156=1156

    P3: 20^2+21^2=29^2  400+441=841  841=841

    P4: 18^2+20^2=26^2  324+400=676  724=676

    So the answers are B and E

  2. trungdung22
    0
    2021-07-31T00:01:31+00:00
    Reply

    Answer:

    b and e

    Step-by-step explanation:

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