It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons

Question

It is known that the electric force of repulsion between two electrons is much stronger than the gravitational attraction. For two electrons at a distance d apart, calculate the ratio of the size of the electrostatic repulsion to that of the gravitational attraction. Use the following data: k = 8.99×10^9 Nm2/C2, e = 1.60×10^-19 C, G = 6.67×10^-11 Nm2/kg2, me = 9.11×10^-31 kg.

in progress 0
Ngọc Diệp 5 years 2021-09-05T09:01:27+00:00 1 Answers 11 views 0

Answers ( )

  1. thienthi
    0
    2021-09-05T09:03:26+00:00
    Reply

    Answer: 348.22*10^(-104)

    Explanation: gravitational force between electrons is gotten using formulae below

    Fg = G ×me×me/d²

    Fg = gravitational force

    G = gravitational constant = 6.67×10^-11 Nm2/kg2

    me = mass of electron = 9.11×10^-31 kg

    d = distance between electrons

    Fg = (6.67×10^-11 × 9.11×10^-31 ×9.11×10^-31) / d²

    Fg = 64.04*10^(-72) /d²

    Fe = k×e ×e/d²

    Where Fe = strength of electric field

    K = electric constant = 8.99×10^9 Nm²/C²

    e = 1.60×10^-19 C

    Fe = 8.99×10^9 × 1.60×10^-19 × 1.60×10^-19/d²

    Fe =2.23*10^(-28)/ d²

    We are to find Fe/ Fg

    =2.23*10^(-28)/ d² ÷ 64.04*10^(-72) /d²

    =2.23*10^(-28)/ d² × d²/64.04*10^(-72)

    = 2.23*10^(-28)/ 64.04*10^(-72)

    = 348.22*10^(-104)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )