In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3} 3 1 ​ of an hour. His swimm

Question

In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3}

3

1

​ of an hour. His swimming partner, Mila, swam \frac {2}{3}

3

2

​ of Logan’s distance in \frac {1}{4}

4

1

​ of an hour.

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Huyền Thanh 3 years 2021-08-12T20:48:38+00:00 1 Answers 193 views 0

Answers ( )

  1. niczorrrr
    0
    2021-08-12T20:50:30+00:00
    Reply

    Answer:

    v = 0.625 m/s

    Step-by-step explanation:

    Given that,

    Total distance is 750 m

    Logan swan 750 m in 1/3 hours

    His swimming partner, Mila, swam 2/3 of Logan’s distance in 1/4 hours.

    Note: We need to find Logan’s average swimming speed.

    Average speed = total distance/total time taken

    v=\dfrac{750\ m}{\dfrac{1}{3}\times 3600\ s}\\\\v=0.625\ m/s

    So, Logan’s average speed is 0.625 m/s.

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