In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves with a constant

Question

In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves with a constant acceleration. The following data are collected for the cart.

t(s) x(m)
0 0
1 4
2 16
3 36
4 64

The acceleration of the cart is most nearly:_____

in progress 0
bonexptip 4 years 2021-07-27T14:27:34+00:00 1 Answers 329 views 0

Answers ( )

  1. Amity
    0
    2021-07-27T14:28:41+00:00
    Reply

    Given :

    Initial velocity , u = 0 m/s² .

    To Find :

    The acceleration of the cart.

    Solution :

    Since, acceleration is constant.

    Using equation of motion :

    x = ut + \dfrac{at^2}{2}\\\\x = \dfrac{at^2}{2}

    Putting, t = 1 s  and x = 4 m in above equation, we get :

    4 = \dfrac{a(1)^2}{2}\\\\a = 8 \ m/s^2

    Therefore, the acceleration of the cart is 8 m/s².

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )