If the open circuit voltage of a circuit containing ideal sources and resistors is measured at 10 , while the current through the short circ

Question

If the open circuit voltage of a circuit containing ideal sources and resistors is measured at 10 , while the current through the short circuit across the circuit is 600 , what would be the power absorbed by a 60 resistor placed across the terminals

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Thu Nguyệt 4 years 2021-08-23T03:12:40+00:00 1 Answers 101 views 0

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  1. ngocdiep
    0
    2021-08-23T03:14:01+00:00
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    Answer:

    Power absorbed by the 60 ohms resistor = 1.02 W

    Explanation:

    Open Circuit Voltage, V_{oc} = 10 V

    Short circuit current, I_{sc} = 600 mA = 0.6A\\

    Thevenin Resistance, R_{th} = V_{oc} /I_{sc}

    R_{th} = 10/0.6\\R_{th} = 16.66 ohms

    R_{l} = 60 ohms

    Current flowing through the terminals, I = V_{oc} /(R_{th} + R_{l} )\\

    I = 10/(60 + 16.66)\\I = 10/76.66\\I = 0.13 A\\

    Power absorbed by the 60 ohms resistor

    P = I^{2} R_{l} \\P = 0.13^{2} * 60\\P = 1.02 W

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