If the child pulls with a force of 20 N for 12.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horizontal, how m

Question

If the child pulls with a force of 20 N for 12.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horizontal, how much work does the child do on the wagon?

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Acacia 5 years 2021-08-28T16:33:50+00:00 1 Answers 19 views 0

Answers ( )

  1. Ladonna
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    2021-08-28T16:34:54+00:00
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    Answer: 217.52 N

    Explanation: The applied force is 20 N, the distance covered is 12.0 m and the angle is 25° above the horizontal.

    Hence the formulae that defines work done is given by

    W = Force × distance

    But since the force has been inclined at an angle θ above the horizontal, the horizontal component of force is neccesary to produce the required motion to make the child do work on the wagon.

    Hence

    Work done = (horizontal component of force) × distance

    Work done = F cos θ × distance

    Work done = 20 cos 25 × 12 = 217.52 N

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