if the area of a rectangle is x^2-9 and one dimension is x-3. what would be the other dimension?

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if the area of a rectangle is x^2-9 and one dimension is x-3. what would be the other dimension?

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King 4 years 2021-08-15T03:55:33+00:00 1 Answers 9 views 0

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    2021-08-15T03:57:07+00:00

    Answer:

    Step-by-step explanation:

    x2-9 = 0

    Area of one dimension = x-3= 0

    So, x2= 9

    Square root on both sides;

    x= +3 and -3

    x-3 is one side

    x+3 is the other dimension

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