If one could transport a simple pendulum of constant length from the Earth’s surface to the Moon’s, where acceleration due to gravity is one

Question

If one could transport a simple pendulum of constant length from the Earth’s surface to the Moon’s, where acceleration due to gravity is one-sixth (1/6) that on the Earth, by what factor would be the pendulum frequency be changed

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MichaelMet 4 years 2021-08-11T06:04:47+00:00 1 Answers 242 views 0

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  1. thuthao
    0
    2021-08-11T06:06:35+00:00
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    Answer:

    The frequency will change by a factor of 0.4

    Explanation:

    T = 2(pi)*sqrt(L/g)

    Since g(moon) = (1/6)g(earth), the period would change by sqrt[1/(1/6)] = sqrt(6) ~ 2.5 times longer on the moon. Since the period & frequency are inverses, the frequency would be 1/2.5 or 0.4 times shorter on the moon.

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