If an object is dropped from a height of meters, the velocity (in ) at impact is given by v= √2gh , where g=9.8m/sec^2 is the acceleration d

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If an object is dropped from a height of meters, the velocity (in ) at impact is given by v= √2gh , where g=9.8m/sec^2 is the acceleration due to gravity.

Required:
a. Determine the impact velocity for an object dropped from a height of 10 m.
b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.

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  1. Answer:

    A.) V = 14 m/s

    B.) h = 36.6 m

    Explanation:

    Given the formula v = √2gh

    where g = 9.8m/sec^2 is the acceleration due to gravity.

    A.) Determine the impact velocity for an object dropped from a height of 10 m.

    Substitute height h in the given formula

    V = √2gh 

    V = √2 × 9.8 × 10

    V = √196

    V = 14 m/s

    b. Determine the height required for an object to have an impact velocity of 26.8 m/sec (~ 60 mph). Round to the nearest tenth of a meter.

    Substitute the velocity in the given formula and make height h the subject of formula.

    26.8 = √2 × 9.8 × h

    Square both sides

    718.24 = 19.6h

    h = 718.24 / 19.6

    h = 36.64 m

    h = 36.6 m

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