I WILL GIVE BRAINLIEST!!! Find the solutions of the quadratic equation 6x^2-6x-2=0 Choose 1 answer: (cho

Question

I WILL GIVE BRAINLIEST!!!

Find the solutions of the quadratic equation 6x^2-6x-2=0

Choose 1 answer:

(choice A)
A
\frac{1}{2}±\sqrt\frac{21}{6}i

(choice B)
B
-\frac{1}{2}±\sqrt\frac{21}{6}i

(choice C)
C
-\frac{1}{2}±\sqrt\frac{21}{6}

(choice D)
D
\frac{1}{2}±\sqrt\frac{21}{6}

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Tryphena 4 years 2021-08-17T11:38:37+00:00 1 Answers 8 views 0

Answers ( )

  1. Gerda
    0
    2021-08-17T11:40:07+00:00
    Reply

    Answer:

    \dfrac{1}{2} \pm \dfrac{\sqrt{21}}{6}

    Step-by-step explanation:

    6x^2 - 6x - 2 = 0

    Divide both sides by 2.

    3x^2 - 3x - 1 = 0

    We compare it to the standard form:

    ax^2 + bx + c = 0

    We have a = 3, b = -3, c = -1.

    To factor, we need two numbers that multiply to ac and add to b.

    ac = 3 * (-1) = -3

    -3 = -3 * 1; -3 + 1 = -2

    -3 = -1 * 3; -1 + 3 = 2

    There are no two integers whose product is -3 and whose sum is -3, so we cannot factor the trinomial. We use the quadratic formula to solve the equation.

    x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

    x = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4(3)(-1)}}{2(3)}

    x = \dfrac{3 \pm \sqrt{9 + 12}}{6}

    x = \dfrac{3 \pm \sqrt{21}}{6}

    x = \dfrac{1}{2} \pm \dfrac{\sqrt{21}}{6}

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )