How many moles of NaOH are needed to react with 200g of H2SO4 using the equation below? H2SO4 + 2NaOH -> Na2SO4 + 2H2O<

Question

How many moles of NaOH are
needed to react with 200g of H2SO4
using the equation below?
H2SO4 + 2NaOH -> Na2SO4 + 2H2O

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Edana Edana 4 years 2021-07-20T19:59:05+00:00 1 Answers 16 views 0

Answers ( )

  1. kimcuc
    0
    2021-07-20T20:00:46+00:00
    Reply

    Answer:

    4.08moles

    Explanation:

    The balanced equation of this reaction is given as:

    H2SO4 + 2NaOH -> Na2SO4 + 2H2O

    From the above balanced equation, 1 mole of H2SO4 is needed to react with 2 moles of NaOH.

    Using the formula below to calculate the number of moles in 200g of H2SO4;

    mole = mass/molar mass

    Molar mass of H2SO4 = 1(2) + 32 + 16(4)

    = 2 + 32 + 64

    = 98g/mol

    number of moles = 200g ÷ 98g/mol

    n = 2.04mol

    Since 1 mole of H2SO4 is needed to react with 2 moles of NaOH.

    Then, 2.04mol of H2SO4 is needed to react with 2.04 × 2/1 = 4.08moles of NaOH.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )