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How many grams of KI would you need to prepare 0.50 g of 7.0% KI (m/m) solution?
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Answers ( )
Answer:
fomula; ( x = mutiplacation btw)
% m/m = m(solute) / m(solution) x 100%
0.50g x 70% = m/m x 100%
0.5g x 70% / 100% = 3.5 g KI
(both % cancle each other)
Explanation:
heads up might be wrong i did it myself