How many gallons of a 15% sugar solution must be mixed with a 5 gallons of a 40% solution to make a 20% solution

Question

How many gallons of a 15% sugar solution must be mixed with a 5 gallons of a 40% solution to make a 20% solution

in progress 0
niczorrrr 4 years 2021-09-05T12:13:58+00:00 1 Answers 31 views 0

Answers ( )

  1. thienan
    0
    2021-09-05T12:15:38+00:00
    Reply

    Answer:

    20 gallons of 15% solution must be mixed with 5 gallons of 40% solution.

    Step-by-step explanation:

    40% of 5 gallons is 2 gallons of sugar

    x represents the number of gallons of solution to be added.

    15% of x is sugar.

    The total amount of sugar must be equal to 20% of the final mixture.

    The end mixture will be x + 5 gallons

    Change percent to decimal for the equation:

    .2(x +5) = .15x +2

    .2x +1 = .15x +2

    .2x – .15x = 2 –1

    .05x = 1

    x = 20

    Check:

    .2(20 +5) = .15(20) +2

    .2(25) = 3 + 2

    5 = 5 true

    This means that adding 20 gallons of the 15% solution is adding 3 gallons of sugar [along with 17 gallons of water] to the 2 gallons of sugar in the original mixture.

    20% of the 25 gallons, 5 gallons, of the final mixture is sugar. 80% [ 3+17 = 20 gallons] is water.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )