How fast would the car need to go to double its kinetic energy?

Question

How fast would the car need to go to double its kinetic energy?

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Doris 4 years 2021-08-11T12:01:20+00:00 2 Answers 13 views 0

Answers ( )

  1. Helga
    0
    2021-08-11T12:02:42+00:00
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    Answer:

    v_{f} = \sqrt{2}\cdot v_{o}

    Explanation:

    Let consider a car travelling at a speed v_{o}. The ratio of final kinetic energy to initial kinetic energy:

    \frac{\frac{1}{2}\cdot m \cdot v^{2}_{f} }{\frac{1}{2}\cdot m \cdot v^{2}_{o}} = 2

    \frac{v_{f}}{v_{o}} = \sqrt{2}

    The final speed is:

    v_{f} = \sqrt{2}\cdot v_{o}

  2. thanhha
    0
    2021-08-11T12:03:14+00:00
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    Answer:

    Explanation:

    Assume:

    Given:

    Kinetic energy, E2 = 2 × E1

    But E = 1/2 × M × v^2

    Where,

    M = Mass

    v = velocity

    E2 = 2 × E1

    = 2 × 1/2 × M × v1^2

    E2 = M × v2^2. ……1

    E1 = 1/2 × M × v1^2. …….2

    Equating equation 1 and 2 to find the final velocity, v2:

    1/2 × M × v1^2 = M × v2^2

    2 × v2^2 = v1^2

    v2^2 = v1^2/2

    v2 = v1/sqrt(2)

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )