How far apart are two electrons if they exert a force of repulsion of 1.5 N on each other (The elementary charge is 1.6 x 10-19 C )?

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How far apart are two electrons if they exert a force of repulsion of 1.5 N on each other (The elementary charge is 1.6 x 10-19 C )?

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Gia Bảo 3 years 2021-08-31T08:00:14+00:00 1 Answers 32 views 0

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  1. nguyetanh
    0
    2021-08-31T08:01:18+00:00
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    Answer:

    The distance between two charges i.e electrons with F= 1.5N is given byr=1.232*10^{-14}

    Explanation:

    To find the distance between 2 electrons, we’ll use the Coulombs Law

    Coulombs Law states the the Force of attraction or repulsion between any two chargers is directly proportional to the product of both charges and inversely proportional to the square of the distance between them.

    Coulombs Law states that (when q₁ = q₂) :

    F=k\frac{q^2}{r^2}

    where

    k=8.9*10^9 Nm^2C^-2

    q=1.6*10^{-19} C

    F = 1.5 N

    Find r

    r^2=k\frac{q^2}{F}

    Substitute the values

    r^2=\frac{(8.9*10^9)(1.6*10^{-19})^2}{1.5}\\r^2= 1.5189*10^{-28}\\r=1.232*10^{-14}

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