How do you solve xx^{2} +4x+3=0?

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How do you solve xx^{2} +4x+3=0?

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Diễm Thu 3 years 2021-08-26T12:14:04+00:00 1 Answers 6 views 0

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    2021-08-26T12:15:38+00:00

    Answer:

    { \tt{ {x}^{2}  + 4x + 3 = 0}} \\ { \tt{(x + 1)(x + 3) = 0}} \\  \\ { \tt{x =  - 1 \:  \: and \:  \:  - 3}}

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )