Given t(x)=-4.9t2+3t+10, what is the value of t(1)?

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Given t(x)=-4.9t2+3t+10, what is the value of t(1)?

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Hưng Khoa 4 years 2021-08-14T16:31:07+00:00 1 Answers 15 views 0

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  1. Edana
    0
    2021-08-14T16:32:20+00:00
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    Step-by-step explanation:

    t(x) = -4.9t² + 3t + 10

    t(1) = -4.9(1²) + 3(1) + 10

    = -4.9 + 3 + 10

    = 8.1

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )