Giải phương trình…….. Question Giải phương trình…….. in progress 0 Môn Toán Gerda 4 years 2020-10-29T14:10:28+00:00 2020-10-29T14:10:28+00:00 1 Answers 67 views 0
Answers ( )
`sqrt{x + 2\sqrt{x – 1}} = 2`
`<=> x + 2sqrt{x – 1} = 4`
`<=> (sqrt{x – 1} + 1)^2 = 2^2`
`=> |sqrt{x – 1} + 1| = 2`
`<=>` \(\left[ \begin{array}{l}\sqrt{x – 1} + 1 = 2\\\sqrt{x – 1} + 1 = -2\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x – 1 = 1\\\sqrt{x – 1} =-3 (l)\end{array} \right.\)
`=> x = 2`