g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for a slit widt

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g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for a slit width of 0.110 mm, using light of wavelength 582 nm?

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Thạch Thảo 3 years 2021-08-25T05:47:10+00:00 1 Answers 1 views 0

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  1. diemthu
    0
    2021-08-25T05:48:21+00:00
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    Answer:

    2

    Explanation:

    We know that in the Fraunhofer single-slit pattern,

    maxima is given by

    a\text{sin}\theta=\frac{2N+1}{2}\lambda

    Given values

    θ=2.12°

    slit width a= 0.110 mm.

    wavelength λ= 582 nm

    Now plugging values to calculate N we get

    0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}

    Solving the above equation we get

    we N= 2.313≅ 2

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