Find the perimeter of the triangle with coordinates A(5,2), B(5,4), and C(1,1). Round to the nearest tenth.

Question

Find the perimeter of the triangle with coordinates A(5,2), B(5,4), and C(1,1). Round to the nearest tenth.

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Khoii Minh 4 years 2021-08-17T14:16:57+00:00 1 Answers 15 views 0

Answers ( )

  1. thongdat2
    0
    2021-08-17T14:18:06+00:00
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    Answer:

    11.1 units

    Step-by-step explanation:

    We solve for this using the formula when using coordinates (x1 , y1) and (x2, y2)

    = √(x2 – x1)² + (y2 – y1)²

    A(5,2), B(5,4), and C(1,1).

    For AB = √(x2 – x1)² + (y2 – y1)²

    = A(5,2), B(5,4)

    = √(5 – 5)² +(4 – 2)²

    = √ 0² + 2²

    = √4

    = 2 units

    For BC = √(x2 – x1)² + (y2 – y1)²

    = B(5,4), C(1,1)

    = √(1 – 5)² +(1 – 4)²

    = √ -4² + -3²

    = √16 + 9

    = √25

    = 5 units

    For AC = √(x2 – x1)² + (y2 – y1)²

    A(5,2), C(1,1)

    = √(1 – 5)² + (1 – 2)²

    = √-4² + -1²

    = √16 + 1

    = √17

    = 4.1231056256 units

    The Formula for the Perimeter of Triangle = Side AB + Side BC + Side AC

    = 2 units + 5 units + 4.1231056256 units

    = 11.1231056256 units.

    Approximately the Perimeter of a Triangle to the nearest tenth = 11.1units

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