Find the inverse of square root f(n) = n – 3. Of(n) = (n + 3) Of-1 (n) = yn +1 Of-1 (n) = -n° +1 Of-1 (n) = -n3 – 3

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Question

Find the inverse of square root f(n) = n – 3.
Of(n) = (n + 3)
Of-1 (n) = yn +1
Of-1 (n) = -n° +1
Of-1 (n) = -n3 – 3

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Mathematics Đan Thu 4 years 2021-09-05T07:42:28+00:00 2021-09-05T07:42:28+00:00 1 Answers 14 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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diemthu · Answer 1 · 2021-09-05T07:43:33+00:00

diemthu

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2021-09-05T07:43:33+00:00 September 5, 2021 at 7:43 am

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Answer:

$f'(n) = n + 3$

Step-by-step explanation:

Given

$f(n) = n - 3$

Required

The inverse

$f(n) = n - 3$

Replace f(n) with y

$y = n - 3$

Swap positions of y and n

$n = y - 3$

Make y the subject

$y = n + 3$

Replace y with f'(n)

$f'(n) = n + 3$