Find the average rate of change of the function over the given interval. Upper R (theta )equals StartRoot 4 theta plus 1 EndRoot​;​[2​

Question

Find the average rate of change of the function over the given interval.
Upper R (theta )equals StartRoot 4 theta plus 1 EndRoot​;​[2​,12​]

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Verity 4 years 2021-08-11T11:43:46+00:00 1 Answers 83 views 0

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  1. taiduc
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    2021-08-11T11:45:33+00:00
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    Answer:

    The average rate of change of the function over the given interval is of 0.4.

    Step-by-step explanation:

    The average rate of change of a function f(x) over an interval [a,b] is given by:

    A = \frac{f(b) - f(a)}{b-a}

    In this question:

    The function is R(\theta) = \sqrt{4\theta + 1}, in the interval [2,12]. So

    R(12) = \sqrt{4(12)+1} = \sqrt{49} = 7

    R(2) = \sqrt{4(2)+1} = \sqrt{9} = 3

    A = \frac{7-3}{12-2} = \frac{4}{10} = 0.4

    The average rate of change of the function over the given interval is of 0.4.

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