Express the time spent to daily life activities during holidays as a fraction of whole day 1. Represent the fractions in pictorial form. 2.

Question

Express the time spent to daily life activities during holidays as a fraction of whole day 1. Represent the fractions in pictorial form. 2. Write the fractions in simplest form. 3. Arrange them in ascending order.

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Đan Thu 4 years 2021-08-09T10:37:52+00:00 1 Answers 45 views 0

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    2021-08-09T10:39:42+00:00

    Answer:

    (II). The fractions in simplest form

    \dfrac{31}{35}, \dfrac{91}{165} and \dfrac{13}{5}

    (III). The fractions in ascending order

    \dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}

    Explanation:

    Given that,

    (I). Represent the fractions in pictorial form

    (II). Write the fractions in simplest form.

    (III). Arrange them in ascending order.

    Suppose, The fractions in pictorial form

    (a). \dfrac{3}{5}+\dfrac{2}{7}

    (b). \dfrac{9}{11}-\dfrac{4}{15}

    (c). \dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}

    We need to write in simplest form

    Using given fraction

    (a). \dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}

    \dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}

    \dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}

    \dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}

    (b). \dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}

    \dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}

    \dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}

    (c). \dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}

    \dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}

    \dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}

    \dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}

    \dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}

    We need to arrange them in ascending order

    Using simplest form

    The simplest fraction in ascending order

    \dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}

    Hence, This is required solution.

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