During a tornado in 2008 the peachtree plaza Westin hotel in downtown Atlanta suffered damage. Suppose a piece of glass dropped near the top

Question

During a tornado in 2008 the peachtree plaza Westin hotel in downtown Atlanta suffered damage. Suppose a piece of glass dropped near the top of the hotel falls 215 meters. What will the velocity of the piece of glass be when it strikes the ground?

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Maris 4 years 2021-08-23T07:18:10+00:00 1 Answers 17 views 0

Answers ( )

  1. thienthi
    0
    2021-08-23T07:19:58+00:00
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    Answer: 64.91 m/s

    Explanation:

    This situation is related to free fall, since we are told the piece of glass “dropped”.

    Now, since this can be considered a one-dimension problem, we can use the following equation:

    V^{2}=V_{o}^{2}+2gd

    Where:

    V is the final velocity of the glass

    V_{o}=0 m/s is the initial velocity of the glass

    g=9.8 m/s^{2} is the acceleration due gravity

    d=215 m is the distance from where the glass fell

    Isolating V:

    V=\sqrt{V_{o}^{2}+2gd}

    V=\sqrt{2(9.8 m/s^{2})(215 m)}

    V=64.91 m/s This is the final velocity of the glass

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