Dinitrogen oxide (N2O) gas was generated from the thermal decomposition of ammonium nitrate and collected over water. The wet gas occupied 1

Question

Dinitrogen oxide (N2O) gas was generated from the thermal decomposition of ammonium nitrate and collected over water. The wet gas occupied 123 mL at 21◦C when the atmospheric pressure was 760 Torr. What volume would the same amount of dry dinitrogen oxide have occupied if collected at 760 Torr and 21 ◦C? The vapor pressure of water is 18.65 Torr at 21◦C. Answer in units of mL.

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Mít Mít 5 years 2021-08-29T22:42:51+00:00 1 Answers 11 views 0

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    0
    2021-08-29T22:44:02+00:00

    Answer:

    119.98 mL

    Explanation:

    Initial volume V1 = 123 ml

    Initial temperature = T1 = 21◦C + 273 = 294 K

    Initial pressure P1 = 760 Torr – 18.65 Torr = 741.35 Torr

    Final volume V2= ???

    Final temperature = T2= 21◦C + 273 = 294 K

    Final pressure P2 = 760 Torr

    From;

    P1V1/T1= P2V2/T2

    P1V1T2 = P2V2T1

    V2 = P1V1T2/P2T1

    V2= 741.35 * 123 * 294/760 * 294

    V2 = 119.98 mL

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