determine the number of moles and mass of the sample of argon occupying 37.8L at STP​

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determine the number of moles and mass of the sample of argon occupying 37.8L at STP​

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Phúc Điền 4 years 2021-08-14T09:22:00+00:00 1 Answers 48 views 0

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  1. binhan
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    2021-08-14T09:23:21+00:00
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    Answer:

    The number of moles and mass of the sample of argon occupying 37.8L at STP​ are 1.6875 moles and 67.41 grams respectively.

    Explanation:

    The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

    Then you can apply the following rule of three: if by definition of STP 22.4 L are occupied by 1 mole of Ar, 37.8 L of Ar are occupied by how many moles?

    amount of moles=\frac{37.8 L* 1 mole}{22.4 L}

    amount of moles= 1.6875 moles

    The atomic weight of Ar is 39.948 g/mol. So the mass of the sample of argon can be calculated as:

    1.6875 moles* 39.948 \frac{g}{mol} = 67.41 grams

    The number of moles and mass of the sample of argon occupying 37.8L at STP​ are 1.6875 moles and 67.41 grams respectively.

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