crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied t

Question

crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate

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Linh Đan 3 years 2021-09-05T16:05:11+00:00 1 Answers 225 views 0

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  1. thuhuong
    0
    2021-09-05T16:06:22+00:00
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    Answer:

    The resulting static friction force acting on the crate is 10 N.

    Explanation:

    Given that,

    Coefficient of static friction = 0.50

    Normal force = 20 N

    We need to calculate the resulting static friction force acting on the crate

    Using formula of static friction force

    f_{s}=\mu_{s}N

    Where, N = normal force

    \mu_{s} = Coefficient of static friction

    Put the value into the formula

    f_{s}=0.50\times20

    f_{s}=10\ N

    Hence, The resulting static friction force acting on the crate is 10 N.

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