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crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied t
Question
crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50. A 20-N force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate
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Physics
3 years
2021-09-05T16:05:11+00:00
2021-09-05T16:05:11+00:00 1 Answers
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Answers ( )
Answer:
The resulting static friction force acting on the crate is 10 N.
Explanation:
Given that,
Coefficient of static friction = 0.50
Normal force = 20 N
We need to calculate the resulting static friction force acting on the crate
Using formula of static friction force
Where, N = normal force
= Coefficient of static friction
Put the value into the formula
Hence, The resulting static friction force acting on the crate is 10 N.