Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalories does it

Question

Consider the reaction below Na2CO3 (aq) + CaCl2 (aq) CaCO3 (s) + 2NaCl (aq) If the releases 39.4 kJ of energy, how many kilocalories does it release? (1 cal = 4.184 J) (Round off answer to 2 decimal place)​

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RuslanHeatt 3 years 2021-08-18T16:18:47+00:00 1 Answers 49 views 0

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  1. Orla
    0
    2021-08-18T16:20:25+00:00
    Reply

    Answer: 9.42

    Explanation: yes

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )